The standard form of $y = 6(x - 2)^2 - 8$ ?

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Answer 1 · 2018-03-18T07:35:27

The quadratic in standard form is $y=6x^2-24x+16$ .

To expand from vertex form, simply do the multiplication and simplify:

$y=6color(blue)((x-2)^2)-8$

$color(white)y=6color(blue)((x-2)(x-2))-8$

$color(white)y=6color(blue)((x^2-4x+4))-8$

$color(white)y=6x^2-24x+24-8$

$color(white)y=6x^2-24x+16$

That's it. Hope this helped!

The standard form of y = 6(x - 2)^2 ­- 8y = 6(x - 2)^2 ­- 8?