The sum of three consecutive odd integers is 189, what are the integers?

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Answer 1 · 2018-05-27T17:12:01

$61 , 63$ and $65$

An odd number take the form: $2k+1$

Hence the next odd numbers must $2k+3$ and $2k+5$

Sum means to add together:

$(2k+1) + ( 2k+3 ) + (2k+5) = 189$

Colect like terms:

$=> 6k + 9 = 189$

$=> 6k = 180$

$=> (6k)/6 = 180 / 6$

$=> k = 30$

$=> 2k+1 = (2*30)+1 = 61$

Hence the odd numbers are $61 , 63 , 65$

Answer 2 · 2018-05-27T17:22:27

See explanation below

stablish a first degree equation

"three CONSECUTIVE odd integers"

Let x, the first, x+2 is the next and x+4 is the next (because they are odd, and odd are build up in this way)

$x+x+2+x+4=189$

$3x=189-6=183$

$x=61$ , the next is $63$ and next is $65$