What are all horizontal asymptotes of the graph y=(5+2^x)/(1-2^x) ?

1 Answer
Sep 22, 2014

Let us find limits at infinity.

lim_{x to +infty}{5+2^x}/{1-2^x}

by dividing the numerator and the denominator by 2^x,

=lim_{x to +infty}{5/2^x+1}/{1/2^x-1}={0+1}/{0-1}=-1

and

lim_{x to -infty}{5+2^x}/{1-2^x}={5+0}/{1-0}=5

Hence, its horizontal asymptotes are

y=-1 and y=5

They look like this:
enter image source here