What are the critical points of $f(x) = 2x^3-3x^2-12x$ ?

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Answer 1 · 2015-10-28T10:59:32

The critical points are $-1$ and $2$ .

To find the critical points of a function, you must compute its first derivative, and then find its zeroes: the first derivative would be

$f'(x)=6x^2-6x-12=6(x^2-x-2)$

So. to find its zeros, we must look for the zeroes of $(x^2-x-2)$ , which are $-1$ and $2$ . So, these are the critical points of $f(x)$ .

What are the critical points of f(x) = 2x^3-3x^2-12xf(x) = 2x^3-3x^2-12x?