What are the critical values, if any, of f(x)= sin|x|?

1 Answer
Dec 20, 2015

{pi/2 + npi|n in ZZ} uu {0}

Explanation:

A critical value c of a function f(x) is a value where f'(c) = 0 or f'(c) is undefined.

The challenge here is to find f'(x) as we do not have a simple rule to handle |x| in differentiation. We could break it into a piecewise function split at x = 0, but let's use another trick in this case.

For all x in RR we have |x| = sqrt(x^2). Thus we can rewrite the function as

f(x) = sin(sqrt(x^2))

Then, applying the chain rule, we have

f'(x) = d/dx sin(sqrt(x^2))

= cos(sqrt(x^2))(d/dxsqrt(x^2))

= cos(sqrt(x^2))(1/(2sqrt(x^2)))(d/dxx^2)

= cos(sqrt(x^2))(1/(2sqrt(x^2)))(2x)

= (xcos(|x|))/|x|

Then, f'(x) is undefined when x=0, and

f'(x) = 0 <=> cos(|x|) = 0

<=> x = pi/2 + npi where n in ZZ

Thus the critical values of sin|x| are

{pi/2 + npi|n in ZZ} uu {0}