What are the excluded values of $f(t) = (t+1)/(t^2+3t+2)$ ?

Question

1354 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-09-04T00:38:47

$t!=-2, -1$

These will occur when the denominator is rendered $0$ .

We can find the excluded values by setting the denominator to $0$ and solving for the variable.

$t^2 + 3t + 2 = 0$

$(t + 2)(t + 1) = 0$

$t = -2 and -1$

Hence, $t!= -2 and -1$ .

Hopefully this helps!

What are the excluded values of f(t) = (t+1)/(t^2+3t+2)f(t) = (t+1)/(t^2+3t+2)?