What are the factors for 6w3+30w2−18w−90=0? Algebra Polynomials and Factoring Factoring Completely 1 Answer Alan P. May 9, 2015 6w3+30w2−18w−90=0 Grouping (6w3+30w2)−(18w+90)=0 (6w2)(w+5)−(18)(w+5) (6x2−18)(w+5) Final check for other obvious common factors: 6(x2−3)(w+5) (x2−3) could be factored as (x+√3)(x−√3) but it is not obvious that this would be any clearer. Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely 2x2−8? Which method do you use to factor 3x(x−1)+4(x−1)? What are the factors of 12x3+12x2+3x? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor 12c2−75 completely? How do you factor x6−26x3−27? How do you factor 100x2+180x+81? See all questions in Factoring Completely Impact of this question 2100 views around the world You can reuse this answer Creative Commons License