Question

What are the polar coordinates of `(1, sqrt3)`?

Answer 1

I found: `(2,pi/3)`

Explanation:

Consider the following diagram:

We can see that the relationships between rectangular and polar coordinates are:
`r=sqrt(x^2+y^2)`
`theta=arctan(y/x)`
and:
`x=rcos(theta)`
`y=rsin(theta)`

In your case:
`x=1`
`y=sqrt(3)`
use them into:
`r=sqrt(x^2+y^2)`
`theta=arctan(y/x)`
to get:
`r=sqrt(1+3)=sqrt(4)=2`
`theta=arctan(sqrt(3))=60^@=pi/3"rad"`