What is a general solution to the differential equation y'-3y=5? Calculus Applications of Definite Integrals Solving Separable Differential Equations 1 Answer Eddie Jun 26, 2016 = gamma e^ {3x} - 5/3 Explanation: y'-3y=5 y'= 3y+5 (y')/(3y+5) =1 int \ (dy)/(3y+5) =int \ dx 1/3ln(3y+5) =x + alpha ln(3y+5) =3( x + alpha) 3y+5 = e^ {3( x + alpha)} = e^ {3x} e^ {3 alpha} = beta e^ {3x} y = 1/3 ( beta e^ {3x} - 5) = gamma e^ {3x} - 5/3 Answer link Related questions How do you solve separable differential equations? How do you solve separable first-order differential equations? How do you solve separable differential equations with initial conditions? What are separable differential equations? How do you solve the differential equation dy/dx=6y^2x, where y(1)=1/25 ? How do you solve the differential equation y'=e^(-y)(2x-4), where y5)=0 ? How do you solve the differential equation (dy)/dx=e^(y-x)sec(y)(1+x^2), where y(0)=0 ? How do I solve the equation dy/dt = 2y - 10? Given the general solution to t^2y'' - 4ty' + 4y = 0 is y= c_1t + c_2t^4, how do I solve the... How do I solve the differential equation xy'-y=3xy, y_1=0? See all questions in Solving Separable Differential Equations Impact of this question 10842 views around the world You can reuse this answer Creative Commons License