What is a general solution to the differential equation y'-3y=5?

1 Answer
Jun 26, 2016

= gamma e^ {3x} - 5/3

Explanation:

y'-3y=5

y'= 3y+5

(y')/(3y+5) =1

int \ (dy)/(3y+5) =int \ dx

1/3ln(3y+5) =x + alpha

ln(3y+5) =3( x + alpha)

3y+5 = e^ {3( x + alpha)} = e^ {3x} e^ {3 alpha} = beta e^ {3x}

y = 1/3 ( beta e^ {3x} - 5)

= gamma e^ {3x} - 5/3