What is a solution to the differential equation dx/dt=t(x-2)? Calculus Applications of Definite Integrals Solving Separable Differential Equations 1 Answer Eddie Jul 11, 2016 x = C e^{ t^2 /2} + 2 Explanation: this is separable dx/dt=t(x-2) 1/(x-2) \ dx/dt=t int \ 1/(x-2) \ dx/dt \ dt =int \ t \ dt int \ 1/(x-2) \ dx =int \ t \ dt ln(x-2) = t^2 /2 + C x-2 = e^{ t^2 /2 + C} = C e^{ t^2 /2} x = C e^{ t^2 /2} + 2 Answer link Related questions How do you solve separable differential equations? How do you solve separable first-order differential equations? How do you solve separable differential equations with initial conditions? What are separable differential equations? How do you solve the differential equation dy/dx=6y^2x, where y(1)=1/25 ? How do you solve the differential equation y'=e^(-y)(2x-4), where y5)=0 ? How do you solve the differential equation (dy)/dx=e^(y-x)sec(y)(1+x^2), where y(0)=0 ? How do I solve the equation dy/dt = 2y - 10? Given the general solution to t^2y'' - 4ty' + 4y = 0 is y= c_1t + c_2t^4, how do I solve the... How do I solve the differential equation xy'-y=3xy, y_1=0? See all questions in Solving Separable Differential Equations Impact of this question 10505 views around the world You can reuse this answer Creative Commons License