Question

What is a solution to the differential equation `dy/dx=sinx/y`?

Answer 1

`y^2=-2cosx+C_2`

Explanation:

`(dy)/(dx)=sinx/y`

separate variables

`intydy=intsinxdx`

`1/2y^2=-cosx+C_1`

`=>y^2=-2cosx+C_2`