What is a solution to the differential equation y'=-9x^2y^2? Calculus Applications of Definite Integrals Solving Separable Differential Equations 1 Answer Eddie Jul 31, 2016 y =1/ (3 x^3 +C) Explanation: y'=-9x^2y^2 this is separable 1/y^2 y'=-9x^2 int \ 1/y^2 y' \ dx=int \ -9x^2 \ dx int \ 1/y^2 \ dy=-9 int \ x^2 \ dx using power rule - 1/y =-3 x^3 +C 1/y = 3 x^3 +C y =1/ (3 x^3 +C) Answer link Related questions How do you solve separable differential equations? How do you solve separable first-order differential equations? How do you solve separable differential equations with initial conditions? What are separable differential equations? How do you solve the differential equation dy/dx=6y^2x, where y(1)=1/25 ? How do you solve the differential equation y'=e^(-y)(2x-4), where y5)=0 ? How do you solve the differential equation (dy)/dx=e^(y-x)sec(y)(1+x^2), where y(0)=0 ? How do I solve the equation dy/dt = 2y - 10? Given the general solution to t^2y'' - 4ty' + 4y = 0 is y= c_1t + c_2t^4, how do I solve the... How do I solve the differential equation xy'-y=3xy, y_1=0? See all questions in Solving Separable Differential Equations Impact of this question 8599 views around the world You can reuse this answer Creative Commons License