What is $f (x) = \int x - 3$ $f(x) = int x - 3$ if $f (2) = 3$ $f(2)=3$ ?

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Answer 1 · 2016-10-15T10:23:23

$f (x) = \frac{x^{2}}{2} - 3 x + 7$ $f(x)=(x^2)/2-3x+7$

$f (x) = \int x - 3 d x$ $f(x)=intx-3 dx$

$= \frac{x^{2}}{2} - 3 x + c$ $=(x^2)/2-3x+c$

Subbing in 2,

$f (2) = \frac{{(2)}^{2}}{2} - 3 (2) + c = 2 - 6 + c = - 4 + c$ $f(2)=((2)^2)/2-3(2)+c=2-6+c=-4+c$

Since $f (2) = 3$ $f(2)=3$ ,

$- 4 + c = 3$ $-4+c=3$

$c = 7$ $c=7$

$:.f(x)=(x^2)/2-3x+7$

What is f(x) = int x - 3 f(x)=∫x−3f(x) = int x - 3 if f(2)=3 f(2)=3f(2)=3 ?