What is her average speed over the entire trip? What is her average velocity over the entire trip?

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Answer 1 · 2018-02-09T08:59:20

Let the distance between A B be $x$ $x$ m.

So time required to travel from A toB @ $5.2$ $5.2$ m/s will be $= \frac{x}{5.2}$ $=x/5.2$ s

Similarly time required to travel from B to A @ $2.9$ $2.9$ m/s will be $= \frac{x}{2.9}$ $=x/2.9$ s

Hence the average speed

$= \frac{total distance traveled}{total time}$ $="total distance traveled"/"total time"$

$= \frac{2 x}{\frac{x}{5.2} + \frac{x}{2.9}}$ $=(2x)/(x/5.2+x/2.9)$

$= \frac{2 \cdot 2.9 \cdot 5.2}{8.1} = 3.721$ $=(2*2.9*5.2)/8.1=3.721$ m/s

Net displacement during total time being zero the average velocity will be zero