What is $int -cosx^2/x$ ?

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Answer 1 · 2017-02-08T22:05:41

$-1/2"Ci"(x^2)+C$

We will use $"Ci"(x)$ , the special cosine integral function.

$int-cos(x^2)/xdx$

Let $t=x^2$ so $dt=2xdx$ :

$=-1/2int(cos(x^2))/x^2(2xdx)=-1/2intcos(t)/tdt$

Which is the cosine integral:

$=-1/2"Ci"(t)=-1/2"Ci"(x^2)+C$

What is int -cosx^2/xint -cosx^2/x?