What is $\int e^{2 x} d x$ $int e^(2x)dx$ ?

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Answer 1 · 2015-11-01T06:48:32

The answer is $\int e^{2 x} d x = \frac{e^{2 x}}{2} + c$ $int e^(2x) dx = (e^(2x))/2 +c$

Note that $\int e^{m x} d x = \frac{e^{m x}}{m} + c$ $int e^(mx) dx = (e^(mx))/m +c$

In your case $m = 2$ $m = 2$

So $\int e^{2 x} d x = \frac{e^{2 x}}{2} + c$ $int e^(2x) dx = (e^(2x))/2 +c$

What is ∫e2xdxint e^(2x)dx?