What is int g(x) = (5-6x^3) / x dx?

1 Answer
Nov 11, 2015

int(5-6x^3)/xdx = 5ln(x) - 2x^3 + c

Explanation:

Umm, you kinda mixed up the notation there buddy.

g(x) = int(5-6x^3)/xdx

Means which function is g(x), if it is that integral

Whereas

int(g(x))dx = (5 - 6x^3)/xdx

Seems to imply that the integral of g(x) is that, so which function is g(x)

I'm guessing you mean the first one, which the way you wrote isn't technically wrong but it's a bit confusing. In that case, we have

int(5-6x^3)/xdx = int(5/x - 6x^2)dx
int(5/x - 6x^2)dx = int(5/x)dx - int(6x^2)dx
int(5/x)dx - int(6x^2)dx = 5intdx/x - 6intx^2dx
5intdx/x - 6intx^2dx = 5(ln(x)) - 6(x^3/3) + c
int(5-6x^3)/xdx = 5ln(x) - 2x^3 + c