What is t = 12.5 s to t = 37.5 s?

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2 Answers
Feb 11, 2018

Acceleration in the time interval
t=12.5s to t=37.5s is 1.92ms2
Acceleration in the time interval
t=0s to t=50s is 0.96ms2

Explanation:

Acceleration is not changing between 12.5 s to 37.5 s
Initial velocityin m/s is =24
Final velocity in m/s is=24
Change in velocity is 24(24)
=24+24
Change in velocity in m/s is48
Time interval in s is =37.512.5
Time interval in s is =25
Rate of change in velocity is
4825
Acceleration in m/s^2 is 1.92
Acceleration in the time interval
t=12.5s to t=37.5s is 1.92ms2
The change in velocity from 0 to 50 s remains the same.
But the time interval is increased.
Hence the acceleration is reduced

Rate of change in velocity is
4850
Acceleration in m/s^2 is 0.96
Acceleration in the time interval
t=0s to t=50s is 0.96ms2

Feb 11, 2018

Average acceleration = change in velocity/total time taken for the change

Now, t=12.5 means 12.52.5=5 rooms along time axis in the graph.

At that point value of velocity is 8 rooms along negative v axis,so value of velocity at 12.5s is 83=24ms

Similarly, t=37.5 means 37.52.5=15 rooms along time axis.

at that point value of velocity is 8 rooms along positive v axis,so velocity at 37.5s is 83=24ms

So,average acceleration in this time interval is 24(24)37.512.5=1.92ms2

Similraly, t=50 means 5012.5=20 rooms along time axis.

so,corresponding velocity value is 8 rooms along positive v axis.

And, at t=0 velocity is 8 rooms along negative v axis,so its value will be 24ms

So,the velocity value is 24ms,

So,average acceleration in this time interval is =24(24)500=0.96ms2