Question

What is the angular momentum of a rod with a mass of `4 kg` and length of `6 m` that is spinning around its center at `1 Hz`?

Answer 1

`P_a=288pi`

Explanation:

`P_a=I*omega`
`I=m*r^2`
`omega=2*pi*f`
`P_a=m*r^2*2*pi*f`
`P_a=4*6^2*2*pi*1`
`P_a=4*36*2*pi`
`P_a=288pi`