Question

What is the angular momentum of a rod with a mass of `4 kg` and length of `6 m` that is spinning around its center at `4 Hz`?

Answer 1

`L=96*pi`

Explanation:

`L=I*omega`
`"L:angular momentum"`
`"I: moment of inertia for rod rotating around its center"`
`I=1/12*m*l^2`
`I=1/12*4*6^2`
`I=12`
`omega=2*pi*f=2*pi*4=8*pi`
`L=8*pi*12`
`L=96*pi`