Question

What is the angular momentum of a rod with a mass of `8 kg` and length of `6 m` that is spinning around its center at `1 7 Hz`?

Answer 1

The angular momentum is `=2563.5kgms^(-1)`

Explanation:

The angular momentum is `L=Iomega`

where `I` is the moment of inertia

and `omega` is the angular velocity

For a rod , `I=(mL^2)/12`

So, `I=8*(6)^2/12=24kgm^2`

`omega=17*2pi=34pi`

`L=24*34pi=2563.5kgms^(-1)`