Question

What is the angular momentum of a rod with a mass of `8 kg` and length of `6 m` that is spinning around its center at `3 Hz`?

Answer 1

The angular momentum is `=452.4kgm^2s^-1`

Explanation:

The angular momentum is `L=Iomega`

where `I` is the moment of inertia

The mass of the rod is `m=8kg`

The length of the rod is `L=6m`

The moment of inertia of a rod, rotating about the center is

`I=1/12*mL^2`

`=1/12*8*6^2= 24 kgm^2`

The frequency is `f=3Hz`

The angular velocity is `omega=2pif=2*3*pi=6pirads^-1`

The angular momentum is

`L=Iomega=24*6pi=452.4kgm^2s^-1`