Question

What is the antiderivative of `1/x^3`?

Answer 1

I found: `-1/(2x^2)+c`

Explanation:

You can write am Indefinite Integral as:
`int1/x^3dx=`
and solve it to find:
`=intx^-3dx=x^(-3+1)/(-3+1)+c=x^-2/-2+c=-1/(2x^2)+c`
If you derive this result you'll find your original `1/x^3` function.