Question

What is the antiderivative of `5/t^2`?

Answer 1

`-5/t+c`

Explanation:

Integrate using the `color(blue)"power rule for integration"`

`color(red)(|bar(ul(color(white)(a/a)color(black)(int(ax^n)dx=a/(n+1)x^(n+1))color(white)(a/a)|)))`

Express `5/t^2" as " 5t^(-2)`

`rArrint(5t^(-2))dt=5/(-1)t^(-1)+c`

`rArrF(t)=-5/t+c`

where c is the constant of integration.