What is the antiderivative of $(5/x)^2$ ?

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Answer 1 · 2015-07-04T21:36:14

I found: $-25/x+c$

I would do this:
$int(5/x)^2dx=int25x^-2dx=$ that can be integrated as a power giving:
$=25(x^-1)/-1+c=-25/x+c$

What is the antiderivative of (5/x)^2(5/x)^2?