What is the antiderivative of $(5/x)^2$ ?

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Answer 1 · 2018-04-06T18:05:36

$-25/x+C$

$(5/x)^2=5^2/x^2=25x^-2$

Recalling that $intx^adx=x^(a+1)/(a+1), a ne -1$ ,

$int25x^-2dx=25x^-1/-1=-25/x+C$

What is the antiderivative of (5/x)^2(5/x)^2?