What is the antiderivative of (7x^3 - 6)/x^2?
1 Answer
May 22, 2016
Explanation:
The first step here is to divide out the function.
(7x^3-6)/x^2=(7x^3)/x^2-6/x^2=7x-6x^-2
rArrint(7x^3-6)/x^2 dx=int(7x-6x^-2)dx Integrate using the
color(blue)" power rule"
int(ax^n)=(ax^(n+1))/(n+1)
rArrint(7x-6x^-2)dx=7/2x^2+6x^-1+c
rArrF(x)=7/2x^2+6/x+c