What is the antiderivative of $9/x^3$ ?

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Answer 1 · 2016-07-07T16:55:17

$int 9/x^3 d x=-9/(2x^2)+C$

$int 9/x^3 d x$

$int 9/x^3 d x=9 int (d x)/x^3$

$int 9/x^3 d x=9 int x^(-3) d x$

$"now use power rule"$

$int 9/x^3 d x=9 [1/(-3+1)x^(-3+1)]$

$int 9/x^3 d x=9[-1/2x^(-2)]$

$int 9/x^3 d x=-9/2*1/x^2$

$int 9/x^3 d x=-9/(2x^2)+C$

What is the antiderivative of 9/x^39/x^3?