What is the antiderivative of $y=sqrt(x)$ from 0 to 5?

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Answer 1 · 2016-10-15T01:13:59

$(2sqrt(125))/3$

$int_0^5sqrtxdx=int_0^5(x)^(1/2)dx->$ We want to convert the function into index form so that we can apply simple power rules.

$int_0^5(x)^(1/2)dx=[(2x^(3/2))/3]_0^5$

$=[(2(5)^(3/2))/3]-[0]$

$=(2(5)^(3/2))/3=(2sqrt(125))/3$

What is the antiderivative of y=sqrt(x)y=sqrt(x) from 0 to 5?