What is the definite integral of $x$ $x$ from 0 to 3?

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Answer 1 · 2014-09-25T04:49:15

$\int_{0}^{3} x d x$ $int_0^3 x dx$

$= {[\frac{x^{2}}{2}]}_{0}^{3}$ $=[x^2/2]_0^3$

$= [\frac{{(3)}^{2}}{2} - \frac{{(0)}^{2}}{2}]$ $=[(3)^2/2-(0)^2/2]$

$= [\frac{9}{2} - \frac{0}{2}]$ $=[9/2-0/2]$

$= [\frac{9}{2}]$ $=[9/2]$

$= 4.5$ $=4.5$

What is the definite integral of xx from 0 to 3?