The Definite Integral
Key Questions
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Answer:
I don't have a one sentence answer
Explanation:
Above the x-axis
Iff(x) is non-negative over the interval[a,b] , then
int_a^b f(x) dx is the area of the region between the graph and thex -axis betweenx=a andx=b Below the x-axis
Iff(x) is non-positive over the interval[a,b] , then
int_a^b f(x) dx is the negative of area of the region between the graph and thex -axis betweenx=a andx=b Example:
int_0^3 sqrt(9-x^2) dx .a=0 andb=3 .
f(x) = sqrt(9-x^2) is never negative, so it is not negative on[0,3] Therefore the integral is equal to the area under the curve and above the
x -axis betweenx=0 andx=3 .The graph of
y = sqrt(9-x^2) is the part ofy^2 = 9-x^2 that has non-negativey -values. It is the upper semicircle forx^2+y^2 = 9
The part betweenx=0 andx=3 is a quarter of a circle with radius 3.graph{y = sqrt(9-x^2)*(sqrt(1.5^2-(x-1.5)^2))/(sqrt(1.5^2-(x-1.5)^2)) [-2.63, 6.137, -0.812, 3.572]}
So
int_0^3 sqrt(9-x^2) dx is1/4 of the area of the circle with radius3
int_0^3 sqrt(9-x^2) dx = (9 pi)/4 -
Answer:
An indefinite integral of a function
f(x) is a family of functionsg(x) for which:g'(x)=f(x) Explanation:
An indefinite integral of a function
f(x) is a family of functionsg(x) for which:g'(x)=f(x) .Examples:
1) if
f(x)=x^3 , then indefinite integral is:int x^3dx=x^4/4+C , because:(x^4/4)'=4*x^3/4=x^3 , andC'=0 for any real constantC 2) If
f(x)=cosx , thenint cosx dx= sinx+C , because:(sinx)'=cosx -
A definite integral is when you integrate a function over a specified interval. When completed you have a definite answer.
Definite Integral because it is bounded
int_0^1 3xdx evaluates to[(3(1)^2)/2 - (3(0)^2)/2] = 3/2 - 0 = 3/2=1.5 Indefinite Integral because it is not bounded
int 3x dx evaluates to(3x^2)/2 + C