What is the derivative of 1/(1 + x^4)^(1/2)1(1+x4)12?

2 Answers
Apr 30, 2015

(-2x^3)/(1+x^4)^(3/2)2x3(1+x4)32

Solution:

rewrite: 1/(1 + x^4)^(1/2) = (1+x^4)^(-1/2)1(1+x4)12=(1+x4)12

Now use the power rule and the chain rule (a combination sometimes called the generalized power rule)

The derivative is:

-1/2 (1+x^4)^(-3/2) (4x^3) = (-2x^3)/(1+x^4)^(3/2)12(1+x4)32(4x3)=2x3(1+x4)32

Apr 30, 2015

The answer is:

This function can be written in this way:

y=(1+x^4)^(-1/2)rArry=(1+x4)12

y'=-1/2(1+x^4)^(-1/2-1)*4x^3=-(2x^3)/sqrt((1+x^4)^3).