What is the derivative of (1 - x)^0.5? Calculus Basic Differentiation Rules Chain Rule 1 Answer maganbhai P. Jul 23, 2018 y=(1-x)^(0.5)=(1-x)^(1/2)=sqrt(1-x) =>(dy)/(dx)=-1/(2sqrt(1-x)) Explanation: Let , y=(1-x)^(0.5) :.y=(1-x)^(1/2) =>(dy)/(dx)=1/2(1-x)^(1/2-1)d/(dx)(1-x) =>(dy)/(dx)=1/2(1-x)^(-1/2) (-1) =>(dy)/(dx)=-1/(2(1-x)^(1/2))=-1/(2sqrt(1-x)) Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of y= 6cos(x^2) ? How do you find the derivative of y=6 cos(x^3+3) ? How do you find the derivative of y=e^(x^2) ? How do you find the derivative of y=ln(sin(x)) ? How do you find the derivative of y=ln(e^x+3) ? How do you find the derivative of y=tan(5x) ? How do you find the derivative of y= (4x-x^2)^10 ? How do you find the derivative of y= (x^2+3x+5)^(1/4) ? How do you find the derivative of y= ((1+x)/(1-x))^3 ? See all questions in Chain Rule Impact of this question 7984 views around the world You can reuse this answer Creative Commons License