What is the derivative of $(2x-1)^3$ ?

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Answer 1 · 2016-02-22T16:56:19

$f'(x) = 6(2x-1)^2$

The derivative of this function involved the power and chain rule, and here is the formula for it

let $f(x) = g^n^n$ , then $f'(x) = ng]^(n-1) (g')$

Given $f(x) = (2x-1)^3$

$n= 3$ , $g(x) = 2x-1$ , $g'(x) = 2$

$f'(x) = 3(2x-1)^2 (2)$

$= 6(2x-1)^2$

What is the derivative of (2x-1)^3(2x-1)^3?