Question

What is the derivative of `arcsin(3-x^2)`?

Answer 1

The derivative for `arcsinu` is:

`d/(dx)[arcsinu(x)] = 1/(sqrt(1-u^2))*(du(x))/(dx)`

`d/(dx)[arcsin(3-x^2)] = 1/(sqrt(1-(3-x^2)^2))*(-2x)`

`= -(2x)/(sqrt(1-(3-x^2)^2))`