What is the derivative of cos(pi*t/6)cos(π⋅t6)? Calculus Basic Differentiation Rules Chain Rule 1 Answer Gerardina C. Jan 8, 2017 -pi/6sin(pi/6t)−π6sin(π6t) Explanation: The variable is t, then f'(t)=-sin(pi/6t)*pi/6 that's -pi/6sin(pi/6t) Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of y= 6cos(x^2) ? How do you find the derivative of y=6 cos(x^3+3) ? How do you find the derivative of y=e^(x^2) ? How do you find the derivative of y=ln(sin(x)) ? How do you find the derivative of y=ln(e^x+3) ? How do you find the derivative of y=tan(5x) ? How do you find the derivative of y= (4x-x^2)^10 ? How do you find the derivative of y= (x^2+3x+5)^(1/4) ? How do you find the derivative of y= ((1+x)/(1-x))^3 ? See all questions in Chain Rule Impact of this question 6098 views around the world You can reuse this answer Creative Commons License