What is the derivative of e^pieπ?

2 Answers
Jul 22, 2015

0

Explanation:

It's a constant function. This question is testing to see that you realize this.

Jul 23, 2015

The derivative is 00. There are several ways to get this answer.

Explanation:

I think it is worth pointing out to students that, while there is one correct answer to the question, "What is the derivative of function ff?", there are often several ways to get to that answer.

Any legitimate way of thinking about the function and correctly applying the rules of differentiation will result in the correct answer.

f(x) = e^pif(x)=eπ

Constant

If we are fortunale enough to recogize that e^pieπ is a constant (close to 2.718^3.14162.7183.1416 whatever that number is!), then we can immediately conclude that d/dx(e^pi) = 0ddx(eπ)=0

Power rule plus chain rule

We know that d/dx(x^pi) = pix^(pi-1)ddx(xπ)=πxπ1. Here we don't have xx, we have instead u = g(x) = eu=g(x)=e, so we need the chain rule:

d/dx(u^pi) = piu^(pi-1) (du)/dxddx(uπ)=πuπ1dudx

In this case (du)/dx = d/dx(e) = 0dudx=ddx(e)=0, so we write:

d/dx(e^pi) = pie^(pi-1)*(0) = 0ddx(eπ)=πeπ1(0)=0

Exponential plus chain

We know that d/dx(e^x) = e^xddx(ex)=ex and d/dx(e^u) = e^u (du)/dxddx(eu)=eududx
Looking at it this way, we have u = g(x) = piu=g(x)=π, whose derivative is 00.

So, in this case we get:

d/dx(e^pi) = e^pi d/dx(pi) = e^pi *0 = 0ddx(eπ)=eπddx(π)=eπ0=0

Logarithmic Differentiation

Let y = e^piy=eπ, so that lny = pilnelny=πlne, but lne =1lne=1, so we have:

lny = pilny=π and differentiation gets us:

1/y dy/dx = 01ydydx=0, so

dy/dx = 0*y = 0e^pi = 0dydx=0y=0eπ=0

But what if i didn't notice that lne = 1lne=1?

It's ok, when we find the derivative, we'll use the chain rule (again) d/dx(lne) = 1/e d/dx(e) = 1/e *0 = 0ddx(lne)=1eddx(e)=1e0=0

The point of my answer is not to confuse, but to tell students that any correct application of differentiation formulas will get the correct answer, and to show some of the possible applications of this general principle.