What is the derivative of $e^{x - 1}$ $e^(x-1)$ ?

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Answer 1 · 2015-08-14T06:43:39

$\frac{d y}{d x}$ $dy/dx$ = $e^{x - 1}$ $e^(x-1)$

Understand
$e^{(s o m e exp r e s s i o n)}$ $e^((some expression))$ is to be differentiated as

(Differentiation of some expression). $e^{(s o m e exp r e s s i o n)}$ $e^((some expression))$

Differentiation of (x - 1) = 1

Hence

$\frac{d y}{d x}$ $dy/dx$ = $e^{x - 1}$ $e^(x-1)$

What is the derivative of e^(x-1)ex−1e^(x-1)?