What is the derivative of f(x) = (arctan (x/2)) + ((5x-1)/(2(x^2) + 4))?

1 Answer
Jun 3, 2018

f'(x)=2/(4+x^2)+(-10*x^2+4x+20)/(2*x^2+4)^2

Explanation:

Note that
(arctan(x))'=1/(1+x^2)
so we get

f'(x)=1/(1+x^2/4)*1/2+(5*(2x^2+4)-(5*x-1)*4x)/(2x^2+4)^2

so we get

f`(x)=2/(4+x^2)+(-10*x^2+4x+20)/(2*x^2+4)^2