What is the derivative of $f(x)=log(sin^2(x))$ ?

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Answer 1 · 2016-06-06T08:51:10

$f' (x)=2*log e*cot x$

From the given $f(x) = log (sin^2 x)$

The formula for finding the derivative of logarithm

$d/dx(log_a u)=1/u*log_a e*d/dx(u)$

$d/dx(f(x))=d/dx(log (sin^2 x))=1/sin^2 x*log e*d/dx(sin^2 x)$

$d/dx(f(x))=d/dx(log (sin^2 x))=1/sin^2 x*log e*2*sin x*cos x$

$d/dx(f(x))=2*log e*cot x$

God bless....I hope the explanation is useful.

What is the derivative of f(x)=log(sin^2(x))f(x)=log(sin^2(x))?