What is the derivative of $f (x) = x ln (x^{3} - 4)$ $f(x)= xln(x^3-4)$ ?

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Answer 1 · 2016-12-04T00:45:30

$f'(x)= (3x^3)/(x^3-4) + ln(x^3-4)$

$f(x) = xln(x^3-4)$

$f'(x) = x*d/dx ln(x^3-4) + ln(x^3-4)*1$ [Product Rule]

$= x* 1/(x^3-4) * (3x^2) + ln(x^3-4)$ [Standard differential and Chain Rule]

$= (3x^3)/(x^3-4) + ln(x^3-4)$

What is the derivative of f(x)= xln(x^3-4)f(x)=xln(x3−4)f(x)= xln(x^3-4)?