Question

What is the derivative of `f(x)= xln(x^3-4)`?

Answer 1

`f'(x)= (3x^3)/(x^3-4) + ln(x^3-4)`

Explanation:

`f(x) = xln(x^3-4)`

`f'(x) = x*d/dx ln(x^3-4) + ln(x^3-4)*1` [Product Rule]

`= x* 1/(x^3-4) * (3x^2) + ln(x^3-4)` [Standard differential and Chain Rule]

`= (3x^3)/(x^3-4) + ln(x^3-4)`