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What is the derivative of $ln (1 - x^{2})$ $ln (1 - x^2)$ ?

1 Answer

Oct 11, 2015

$\frac{- 2 x}{1 - x^{2}}$ $(-2x)/(1-x^2)$

Explanation:

Use $\frac{d}{d x} (ln u) = \frac{1}{u} \frac{d u}{d x}$ $d/dx(lnu) = 1/u (du)/dx$ .

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