What is the derivative of ${ln x}^{\frac{1}{2}}$ $lnx^(1/2)$ ?

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Answer 1 · 2016-09-24T18:50:52

$= \frac{1}{2 x}$ $=1/ (2x)$

$\frac{d}{d x} ({ln x}^{\frac{1}{2}})$ $d/dx ( ln x^(1/2))$

$= \frac{d}{d x} (\frac{1}{2} ln x)$ $=d/dx ( 1/2 ln x)$

$= \frac{1}{2} \frac{d}{d x} (ln x)$ $=1/2 d/dx (ln x)$

$= \frac{1}{2} (\frac{1}{x})$ $=1/2 (1/ x)$

$= \frac{1}{2 x}$ $=1/ (2x)$

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