What is the derivative of $\frac{ln x}{4 x^{2}}$ $lnx/(4x^2)$ ?

Question

3051 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-12-24T18:34:12

Quotient rule, which states for $y = \frac{f (x)}{g (x)}$ $y=f(x)/g(x)$ , $y'=(f'(x)g(x)-f(x)g'(x))/g(x)^2$ , will help us here.

$(dy)/(dx)=((1/x)(4x^2)-lnx(8x))/(4x^4)$

$(dy)/(dx)=(4x-8xlnx)/(4x^4)=(1-2lnx)/(x^3)$

What is the derivative of lnx/(4x^2)lnx4x2 lnx/(4x^2)?