What is the derivative of $pi^sinx$ ?

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Answer 1 · 2016-07-09T03:54:01

Letting $y=pi^(sin(x))$ , we get

$y' = pi^(sin(x)) * cos(x) * ln(pi)$ by the chain rule.

The derivatives of exponential functions with base $a$ states that

$d/dx[a^(x)] = a^(x) * ln(a)$ .

What is the derivative of pi^sinxpi^sinx?