What is the derivative of $-sin^2(x)$ ?

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Answer 1 · 2016-02-19T08:12:34

$f'(x)=-sin2x$

Given equation is $f(x)=-sin^2(x)$
We will use chain rule here.

So, $f'(x)=-d/dx(sin^2(x))=-2sinxd/dx(sinx)=-2sinxcosx$

Simplifying the above equation gives you the answer.

What is the derivative of -sin^2(x)-sin^2(x)?