What is the derivative of #sin^3x#? Calculus Differentiating Trigonometric Functions Limits Involving Trigonometric Functions 1 Answer roy · Aviv S. Mar 3, 2018 Basic formula: #d/(dx)x^n=nx^(n-1)# #d/dx(sinx)=cosx# Now, let's move to the question: #color(white)=d/dx(sin^3x)# #=(3sin^2x)×(d/dx(sinx))# #=3sin^2xcosx# It may be useful for you👍 Answer link Related questions How do you find the limit of inverse trig functions? How do you find limits involving trigonometric functions and infinity? What is the limit #lim_(x->0)sin(x)/x#? What is the limit #lim_(x->0)(cos(x)-1)/x#? What is the limit of #sin(2x)/x^2# as x approaches 0? Question #99ee1 What is the derivative of #2^sin(pi*x)#? Question #eefeb Question #af14f How do we find the derivative of #tanx# from first principal? See all questions in Limits Involving Trigonometric Functions Impact of this question 86984 views around the world You can reuse this answer Creative Commons License