What is the derivative of sin(3x)sin(3x)?

1 Answer
Jun 14, 2016

3cos(3x)3cos(3x)

Explanation:

The chain rule is a tool for differentiating composite functions, that is, a function inside a function.

Here, we have sin(3x)sin(3x). This can be thought of as the function 3x3x being put inside of the function sin(x)sin(x).

When finding the derivative of such a function, the chain rule tells us that the derivative will be equal to the derivative of the outside function with the original inside function still inside of it, all multiplied by the derivative of the inside function.

So, for sin(3x)sin(3x), the derivative the sin(x)sin(x), the outside function, is cos(x)cos(x).

So, the first part of the chain rule, the differentiated outside function with the inside function unchanged, gives us cos(3x)cos(3x). Then, this is multiplied by the derivative of the inside function. The derivative of 3x3x is 33, so the overall derivative is cos(3x)xx3=3cos(3x)cos(3x)×3=3cos(3x).

We can generalize this to all derivatives of sine functions:

d/dxsin(f(x))=cos(f(x))*f^'(x)