What is the derivative of sin 5xsin5x?

1 Answer
Jan 19, 2016

5cos5x5cos5x

Explanation:

Use the chain rule.

The chain rule states that, in the case of a sine function,

d/dx[sinu]=cosu*(du)/dxddx[sinu]=cosududx

More generally, the chain rule says to identify an inside function and an outside function. Here, the outside function is sinxsinx, and the inside function is 5x5x.

The chain rule then says to differentiate the outside function, and the derivative of sinxsinx is cosxcosx. With this derivative, plug in the inside function: this gives us cos5xcos5x.

The final step of this is to multiply the function by the derivative of the inside function, and the derivative of 5x5x is 55.

Thus, the derivative of the whole function is cos5x*5cos5x5, or 5cos5x5cos5x.

Using the rule given at the top:

d/dx[sin5x]=cos5x*d/dx[5x]=cos5x*5=5cos5xddx[sin5x]=cos5xddx[5x]=cos5x5=5cos5x