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What is the derivative of $\sqrt{3 x}$ $sqrt(3x)$ ?

1 Answer

Feb 12, 2016

$\frac{\sqrt{3}}{2 \sqrt{x}}$ $sqrt(3)/(2sqrt(x)$

Explanation:

If $y = \sqrt{3 x}$ $y=sqrt(3x)$

$\frac{d y}{d x} = \frac{d (\sqrt{3} \cdot \sqrt{x})}{d x}$ $dy/dx= (d (sqrt(3)*sqrt(x)))/dx$

$XXX = \sqrt{3} \cdot \frac{d \sqrt{x}}{d x}$ $color(white)("XXX")=sqrt(3)*(d sqrt(x))/dx$

$XXX = \sqrt{3} \cdot \frac{{d x}^{\frac{1}{2}}}{d x}$ $color(white)("XXX")=sqrt(3)* (dx^(1/2))/dx$

$XXX = \sqrt{3} \cdot \frac{1}{2} x^{- \frac{1}{2}}$ $color(white)("XXX")=sqrt(3)*1/2x^(-1/2)$

$XXX = \sqrt{3} \cdot \frac{1}{2 \sqrt{x}}$ $color(white)("XXX")=sqrt(3)*1/(2sqrt(x))$

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